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2 years ago

How do you find the exterior angle of a polygon?

Mathematics

1 answer:

trasher [3.6K]2 years ago

7 0

The sum of the measures of the interior angles of a polygon with n sides is (n – 2)180.

The measure of each interior angle of an equiangular n-gon is.

If you count one exterior angle at each vertex, the sum of the measures of the exterior angles of a polygon is always 360°.

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PLEASE HELP ALGEBRA WORK

g100num [7]

I believe it is A

Hope this answer helps

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3 years ago

Write an equation that shows the relationship between x and y.

svp [43]

Write an equation to describe the relationship between the corresponding values of x and y shown in the table.

8 0

3 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

2 years ago

3(x – 5) = 2(x – 5) + x solve for x and number of soultions

ArbitrLikvidat [17]

Answer:

Step-by-step explanation

3x-15=2x-10+x

3x-15=3x-10

in this step, problem happens

becoz both side doesnt equal, no ans can be proven

4 0

3 years ago

Read 2 more answers

The washer in the image has an inner diameter of 1/4 inch. The outer diameter measures 3/4 inch, and the washer is 1/4 inch thic

Talja [164]

Answer:

0.14 lb . . . closest choice is 0.11 lb

Step-by-step explanation:

The inside and outside radii are 1/8 in and 3/8 in, respectively. Then the area of the top of the washer is ...

A = π(R² -r²) = π((3/8)² -(1/8)²) = π(9/64 -1/64) = π/8 . . . square inches

The height of the stack of 5 washers will be 5×(1/4 in) = 5/4 in. So, the volume of material in the stack of washers is ...

V = Bh = (π/8)(5/4) = 5π/32 . . . cubic inches

The weight of material is the product of volume and density, so is ...

W = (5π/32 in³)(0.285 lb/in³) ≈ 0.1399 lb ≈ 0.14 lb

_____

<em>Comment on the question</em>

Since this answer does not correspond to any of the offered choices, we suggest you ask your teacher to work this out for you. We suspect they will have difficulty justifying any of the answer choices shown here. (0.11 lb corresponds to 4 washers, not 5.)

5 0

3 years ago