Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.
Ok so if you notice every choice is solved for a, all you have to do is isolate "a" in 7a-8b=10x. Start by moving 8b to the other side and to change the sign. Now it is 7a = 10x + 8b. Then divide everything by 7 and you get a = (10x + 8b)/7
Answer:
The least value of (r+s) is (12+14)=26
Step-by-step explanation:
Well, first let us solve equation of 11(s-1)=13(r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.
To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).
Finally, the least value of (r+s) is (12+14)=26.
Answer:
The question 
after change the mixed number to improper & using KCF will become : 
Option B is correct option.
Step-by-step explanation:
We need to change the mixed number to improper & use KCF to rewrite the question.
The expression is:
First converting mixed fraction into improper fraction
Multiply whole number with the denominator i,e (3*2=6) now add the numerator i.e (6+1) = 7/2
Solving:
Using KCF
KCF stands fro Keep it, Change it, Flip it.
It is used when division sign is converted to multiplication the term (1/3) is reversed to (3/1)
So, our expression will be
So, The question after change the mixed number to improper & using KCF will become :
Option B is correct option.
Answer:
the 3rd one
Step-by-step explanation:
