Answer:
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Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;



x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Answer:
It is the last option.
Step-by-step explanation:
The diagonals of a rhombus (KM and NL ) are perpendicular. That is shown by the diagonals having slopes of 1 and -1.
Recall that when 2 lines are perpendicular then m1 * m2 = -1 , where m1 and m2 are the slopes of the lines.
Answer: 2 5/8
Step-by-step explanation:
you divide and get the answer
The second and fourth one are rational. They are perfect squares and are terminating or are fractions