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3 years ago

X2=xscbhgedvc jwhdbc *jksdddfhb1287378216378123123213=21378123y182+1273y21e2ew

Mathematics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

Thank you :)

Step-by-step explanation:

I needed this man, thank you so much for making my day...

Andreas93 [3]3 years ago

3 0

Sad I need it too :(

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At Thanksgiving, Mrs. Jones overcooked the turkey so all but 5 of it had to be thrown away. The 8 people at dinner that

VashaNatasha [74]

<em>The question has inconsistent or incomplete data, so I'm filling the holes with key data.</em>

Answer:

<em>Every people at dinner received one-tenth of the original turkey= 0.1</em>

Step-by-step explanation:

<u>Proportions</u>

If some fraction a/b of a whole total M is to be computed and later removed, we proceed as follows

* Compute the portion to be removed as a/b*M

* Subtract it from the total quantity: M-a/b*M=M(1-a/b)

I'm assuming 1/5 of the turkey was lost due to overcooking. It means that (1-1/5) of the turkey remained for dinner, that is, 4/5 of the turkey.

Each people at dinner received the same amount of the remaining, so we must divide 4/5 by 8, to get 4/40, or 1/10. It means that every people at dinner received one-tenth of the original turkey

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3 years ago

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What % of the people surveyed own fish

Dima020 [189]

A, because you take 0.04 and 0.08 and add them together. you get 0.12 which can be converted to 12% or A

4 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!! I learned this two years ago and I don't remember how to do this anymore!!!!!!

Otrada [13]

So remember the acronym "SOH CAH TOA"

Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent

Opposite = Side that doesn't touch the angle
Adjacent = Side that touches the angle
Hypotenuse = Side that is across from the right angle

So we see that side a doesn't touch angle $\alpha$ , hence making it the opposite side. And we see that side b is across from the right angle, making it the hypotenuse. <u>Using this info, $\sin \alpha = \frac{a}{b}$ </u>

So we already know from part A that side b is the hypotenuse. And also since side c touches the angle, it is the adjacent.<u> Using this info, $\cos \alpha = \frac{c}{b}$ </u>

Next, it has been established that side c is the adjacent and side a is the opposite side. <u>Using this info, $\tan \alpha = \frac{a}{c}$ </u>

4 0

3 years ago

Please help! I've already answered part a, I don't understand what part b is asking.

Luba_88 [7]

Step-by-step explanation:

So, there is something known as a removable discontinuity, and it's essentially where you can define f(x) using the most simplified fraction, where you could normally not define f(x).

So we have the following equation:

$f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}$

As you may know, we cannot divide a number by the value of zero. When the denominator is equal to zero, on the graph this will appear as a vertical asymptote, where x approaches the value that makes the denominator zero, but never actually reaches it.

If you look at each denominator, you can set them equal to zero to find the vertical asymptotes

x+1 = 0

x=-1

There should be a vertical asymptote at x=-1, since it would make two of the denominators equal to -1, but let's divide the two fractions first.

Original Equation

$f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}$

Keep, change, flip

$f(x) = (\frac{x+5}{x+1}*\frac{(x-4)(x+1)}{(x+3)(x-2)})-\frac{1}{x-2}$

Multiply the two fractions

$f(x) = (\frac{(x+5)(x-4)(x+1)}{(x+1)(x+3)(x-2)})-\frac{1}{x-2}$

Notice how the x+1 is in the numerator and fraction? That means we can cancel it out!

$f(x) = (\frac{(x+5)(x-4)}{(x+3)(x-2)})-\frac{1}{x-2}$

In this simplified version of the fraction, we can technically define f(-1), but in the original version, since it's not defined there is a removable discontinuity at x=-1, meaning there is no vertical asymptote, but the function is still not defined at f(-1), and there will be a hole at that point.

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2 years ago

If Jeremy is in the 90th percentile in the main office test scores is 180 with a standard deviation of 15 which of the following

Alika [10]

199.

the z score for the 90th percentile is 1.28, so you can solve the equation

$\frac{x-180}{15} = 1.28$

which gets you the 199

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3 years ago