Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is
.
Answer:
5.02 m/s
Step-by-step explanation:
We are given that
Mass of block,m=8 kg
Initial velocity,u=3.2 m/s
Net force ,F=10 N
Distance,s=6 m
We have to find the approximate final velocity of the block.
We know that 
Using the formula

We know that

Using the formula


38.50 = 100%
31.57 = ?
Multiply: 31.57 x 100 = 3,157
Divide: 3,157 ÷ 38.50 = 82%
100-82= 18% discount
Answer:
2(3+7)=20 and 20 is a multiple of 4
Step-by-step explanation:
4 times 5 equals 20, which makes it a multiple of 4
3 and 7 are both odd, and added together get 10. Times that by 2 and you get 20