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Ksivusya [100]
4 years ago
11

Help please ?

Mathematics
1 answer:
ehidna [41]4 years ago
6 0

Answer:

t(c)=\frac{t-10}{8} determines the time you used the kayak for at a specific cost you paid.

Step-by-step explanation:

The inverse of a function, is the function or rule formed by reflecting the line over y=x. This means essentially that all (x,y) values from the original function switch to (y,x).

(x,y)--->(y,x) in the new function.

If the function has points (-3,4) and (5,-2) then the inverse has points (4,-3) and (-2, 5).

For the original function, we used the time we had the kayak to compute the cost. For 3 hours, it cost c(3)=8(3)+10=$34. (3,34) for (t,c).

For the inverse, we will find the time we had the kayak for a specific cost. To write it we switch input(x) and output(y) and solve for y.

y=8x+10

x=8y+10

x-10=8y

\frac{x-10}{8} =y

This is the inverse function, We replace (x,y) with (c,t).

t(c)=\frac{t-10}{8}



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Answer:

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Step-by-step explanation:

From the question we are told that

    The temperature at 8300ft is 194.23 °  F

    The  temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

      m  =  \frac{ 202.2 - 194.23}{ 4200 - 8300}

=>     m  = 0.001943  ^o  F / ft  

Generally the according to the point slope formula is

      y - y_1  =  m(x -x_1 )

=>   y - 194.23 =  -0.001943 (x - 8300 )

=>  y - 194.23 =  -0.001943x + 16.1269

=>  y  =  -0.001943x + 210.3569

Now we are given from the question that   x =  2600 ft

Then  

         y  =  -0.001943(2600) + 210.3569

=>      y  =  205.3051 \  °F

   

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Given a function f(x)=2x^2+3, what is the average rate of change of f on the interval [2, 2+h]?
AveGali [126]

Answer:

4x+2h

Step-by-step explanation:

The average rate of change of a continuous function,

f

(

x

)

, on a closed interval  

[

a

,

b

]

is given by

f

(

b

)

−

f

(

a

)

b

−

a

So the average rate of change of the function  

f

(

x

)

=

2

x

2

+

1

on  

[

x

,

x

+

h

]

is:

A

r

o

c

=

f

(

x

+

h

)

−

f

(

x

)

(

x

+

h

)

−

(

x

)

     

=

f

(

x

+

h

)

−

f

(

x

)

h

 

 

 

 

 

...

.

.

[

1

]

     

=

2

(

x

+

h

)

2

+

1

−

(

2

x

2

+

1

)

h

     

=

2

(

x

2

+

2

x

h

+

h

2

)

+

1

−

2

x

2

−

1

h

     

=

2

x

2

+

4

x

h

+

2

h

2

−

2

x

2

h

     

=

4

x

h

+

2

h

2

h

     

=

4

x

+

2

h

Which is the required answer.

Additional Notes:

Note that this question is steered towards deriving the derivative  

f

'

(

x

)

from first principles, as the definition of the derivative is:

f

'

(

x

)

=

lim

h

→

0

 

f

(

x

+

h

)

−

f

(

x

)

h

This is the function we had in [1], so as we take the limit as  

h

→

0

we get the derivative  

f

'

(

x

)

for any  

x

, This:

f

'

(

x

)

=

lim

h

→

0

 

4

x

+

2

h

     

=

4

x

4 0
3 years ago
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