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3 years ago

Maclaurin series of sinx

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

cos(u) and sin(u) can be expanded in with a Maclaurin series, and cos(c) and sin(c) are constants.

Step-by-step explanation:

thats it

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Which decimal is equivalent to 8%

Nikitich [7]

Answer:

$0.08$

Step-by-step explanation:

Given : 8%

To find the decimal value of the percentage number

Remove the percentage symbol with 100 in the denominator

gives

$\frac{8}{100}\\$

Now taking the numerator to the decimal place equal to the number of zeros in the denominator or simply divide denominator with numerator.

Gives = $0.08$

So, the decimal equivalent of the given value is $0.08$

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3 years ago

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Simplify to create an equivalent expression.

sergejj [24]

Answer:

a.) -20p - 2

Step-by-step explanation:

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You Try:<br> True or False: (-8) + 9 = 9+ (-8)<br> Show your work to prove your answer.

poizon [28]

Answer:

true

Step-by-step explanation:

(-8) + 9=1

9+(-8)=9-8=1

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3 years ago

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find an equation for the line with the given properties Express the equation in slope intercept form.

zubka84 [21]

In slope Intercept for it is ...y=2x+3

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2 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

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3 years ago