Find the least common multiple of 8b^2 and 5n^3
2 answers:
For this case, we have that by definition, the LCM of two or more natural numbers, is the smallest natural number that is a common multiple of all of them.
Then, the LCM of 8 and 5 is the smallest positive integer that divides both numbers without leaving residues.
Multiplos:
8: 8,16,24,32,40,48
5: 1,10,15,20,25,30,35,40,45
Thus, the LCM of 8 and 5 is 40.
Therefore the LCM of the given expressions is:
Answer:
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In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).
Remember to use that left-to-right orientation for interval notation!
The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).
Remember to use that left-to-right orientation for interval notation!
The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).