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horsena [70]
3 years ago
7

Can someone give me the correct solution to the inequality of 3x<-21?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

x < -7

Step-by-step explanation:

3x < -21

<u>Step 1:  Divide both sides by 3</u>

3x < -21

3x / 3 < -21 / 3

x < -7

Answer: x < -7

levacccp [35]3 years ago
8 0
X < -7 that is your answer
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Brut [27]

Answer:

44, 3.5

11 x 4= 44

3.5 x 1 = 3.5

3 0
3 years ago
Alex buys 2 1/2 pounds of grapes. He buys 1 1/4 times as many pounds of apples as grapes. How many pounds of apples does he buy?
galina1969 [7]
Given:
grapes = 2 1/2 pounds
apples = 1 1/4 times as many pounds as grapes.

For easier computation, let us convert these fractions into numbers with decimal places.

2 1/2 pounds = 2.50 pounds
1 1/4 times = 1.25

Apples = 2.50 pounds * 1.25 = 3.125 pounds of apples.

Or we still use fractions. We need to convert the mixed fractions into improper fractions.

2 1/2 = 5/2
1 1/4 = 5/4

5/2 * 5/4 = 5*5 / 2*4 = 25/8 is simplified to 3 1/8 pounds
3 0
3 years ago
Find the first four term of (1 – 2y) –4​
antiseptic1488 [7]

Answer:

that would be 1

Step-by-step explanation:

All of the terms is 1,2,y,and 4 and 1 is the first one.

7 0
3 years ago
Find x. <br><br> Please help! Oh
Reika [66]
X = 8.5 because 8.5 x 2 = 17 and 17 + 1 = 18
4 0
3 years ago
Read 2 more answers
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
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