By definition we have an integer number given by:
An integer is an element of the numeric set that contains the natural numbers {N} = {1,2,3,4, ...}, its opposite and zero.
On the number line we find the negative numbers to the left of the zero and to its right the positive numbers.
We have then, according to the definition, that the following are whole numbers:
-527, 1
Answer:
B = {x | x is an integer}
-527 ∈ B
1 ∈ B
option D
Since those are the zeros, we can say that the equation would have to be
x(x-1)(x-6), then we just expand to get x^3 - 7x^2 + 6x
Christmas font Courier South Crystal Downs matemáticas
Answer:
Step-by-step explanation:
<span>g(x) = x^2 + 3x - 4 (please be sure to use " ^ " to denote exponentiation).
This function factors into g(x) = (x+4)(x-1), and so the zeros are -4 and +1.
If we shift this graph 5 units to the left, we get h(x) = (x+5)^2 + 3(x+5) - 4.
The new zeros will be -4-5 and 1-5, or -9 and -4.
</span>
