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4 years ago

Hey can someone help me with this I think I know the answer but I'm not sure

Mathematics

2 answers:

Elden [556K]4 years ago

7 0

Answer:

All I can tell u is that the exponent is the number of times the decimal moves

Step-by-step explanation:

AfilCa [17]4 years ago

4 0

As the other answer stated, the exponent is the number of times the decimal moves. If the decimal moves forward, the exponent is positive, and if the decimal moves backward, the exponent is negative.

-580,000 = -5.8 × 10^5

26,400,000 = 2.64 × 10^7

0.000135 = 1.35 × 10^-4

0.000002 = 2 × 10^-6

155,000,000 = 1.55 × 10^8

0.00000014 = 1.4 × 10^-7

0.0003 = 3 × 10^-4

7,800,000 = 7.8 × 10^6

0.0467 = 4.67 × 10^-2

3,500 = 3.5 × 10^3

900 = 9 × 10^2

1,000,000,000 = 1 × 10^9

<h3>The answer to the riddle is "In a hambulance".</h3>

<em>Hope this helps!</em>

~ V.

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If six angles of a heptagon have measures of 122, 153, 168, 105, 162, and 87, what is the measure of the seventh angle?

xxTIMURxx [149]

Answer:

he seventh angles measure is 103

Step-by-step explanation:

Interior angles = (number of side in the polygon - 2) times 180.

So Heptagon interior angles = (7-2)(180) = 900

To find the missing angles add all the given angles together (122, 153, 168, 105, 162, and 87) = 797.

Now The measure of the seventh angles = total angles measure - the six given angles,

The seventh angles measure is 103

900 - 797 = 103

7 0

3 years ago

In a poll, 74% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted o

Maksim231197 [3]

Answer:

324

Step-by-step explanation:

given that in a poll, 74% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?"

i.e. Sample proportion $p=0.74\\q =1-p =0.26\\$

Margin of error = 4% = 0.04

Confidence level =90%

Z critical value for 90% = 1.645

Margin of error = 1.645 * std error

Hence std error = $\frac{0.04}{1.645} \\=0.0243$

Std error is also equal to

$\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.74(0.26)}{n} } =0.0243\\\sqrt{n} =18..05\\n = 325.83~324$

Sample size should be 324.

The formula is sample size = (Z critical value)^2 (pq)/(Margin of error )^2

3 0

4 years ago

PLZZ could someone help me out with this and explain

jenyasd209 [6]

Answer:

It would be D because X^2 is different from 3x you would just multiply X^2 by 1 and 3x by 1 to get x^2+3x

3 0

3 years ago

Read 2 more answers

The regular price of a pair of jeans is x dollars. Let f(x) = x - 15, where frepresents the price of

Phoenix [80]

Answer:

(f o g)(x) = 0.8x - 15

Step-by-step explanation:

(f o g)(x) = f(g(x)) = applying first g(x), and then using that result as input value for f(x).

so, first we discount by 20% and use g(x)

g(x) = 0.8x

and then we use that in f(x)

f(0.8x) = 0.8x - 15

and that is the result.

8 0

3 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

4 years ago

Hey can someone help me with this I think I know the answer but I'm not sure​

Hey can someone help me with this I think I know the answer but I'm not sure