Please help {[(3^8) x (2^-5) x (9^0)]^-2} x [(2^-2)/(3^3)]^4 x (3^28)
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Answer: <em>23.7</em>
Step-by-step explanation:
<em>Let's calculate the acute angle at the base of the triangle:</em>
<em>180° - 90° - 40° = 50°</em>
<em>Find side x:</em>
To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2.
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)