Answer:
It’s 15/3+(2•11)
Step-by-step explanation:
The answer is -a + b = 0
If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation: a + b = 4
Unknown equation: -a + b = ?
We know that a = 2 and be = 2, thus:
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0
Let's check it out:
Known equation: a + b = 4
Unknown equation: -a + b = 0
________________________
Add them up: 2b = 4
b = 4/2 = 2
a + b = 4
a = 4 - b
a = 4 - 2
a = 2
So, the second equation is correct.
Sin 45=x/s
s=x/sin 45
s=x√2
sin 60=s/12√6
(√3/2)(12√6)=x√2
(18√2)/√2=x
x=18
Answer:
Step-by-step explanation:
F(x)= (x − a)2 + b
Rewrite the equation as (X-a)2 + b= f(X) (X-a)2 + b= f(X) subtract (x-a)^2 from both sides of the equation b=f(x)- (x-a)^2
Answer:
See attachment >_<
Step-by-step explanation:
Because the line includes the point 
, we'll begin our line at this coordinate.
The slope is 
, or, 
. Slope is formatted in the 
in the line over its 
. Or, 
. This means the line rises units and runs 
unit.
From our beginning point, , move up seven units and then to the right one unit.
If this line was negative (it would have a negative slope), we would run to the left. However, we have a positive slope, so we will run to the <em>right.</em>
By doing this, we land on the point 
. Draw a line through this point with our beginning coordinate . This is our graphed line. I've attached a photo as well :)
Good luck ^^
