3 years ago

Show that only one n, n+2 and n+4 are divisible by 3

Mathematics

1 answer:

babymother [125]3 years ago

3 0

N+2 divide 3 so it should be correct hope it helped

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7nadin3 [17]

Answer:

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}$

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}$

Step-by-step explanation:

$f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0$

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Answer:

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