Answer:
Step-by-step explanation:
The area of a trapezoid has a formula of:
Area = (a + b) h / 2
Using the formula, we can easily find the height of the trapezoid.
<span>Area = (a + b) h / 2
</span>2250 = (80 + 100) h / 2
2250 = 180h / 2
2250 = 90h
h = 25 centimeters
So the height of the trapezoid is 25 centimeters.
1,000,000+3000,000+30,000+4,000+400+50+7
Answer:
<u>B. 2</u>
To find MAD, find the mean of the set, then find how far each number is from the mean. Next, find the mean of THAT set of numbers. Yea, I know it's a bit confusing... don't worry!
Find the mean of the set:
12 + 10 + 10 + 8 + 6 + 7 + 7 + 12
72
72 / 8
<u>9</u>
Find how far each number is from 9:
12 - 9 = <u>3</u>
10 - 9 = <u>1</u>
10 - 9 = <u>1</u>
9 - 8 = <u>1</u>
9 - 6 = <u>3</u>
9 - 7 = <u>2</u>
9 - 7 = <u>2</u>
12 - 9 = <u>3</u>
Find the mean of that number set:
{3, 1, 1, 1, 3, 2, 2, 3}
3 + 1 + 1 + 1 + 3 + 2 + 2 + 3
16
16 / 8
<u>2</u>
<u>So the answer is 2!</u>
Not so hard after all :D
1 In general, given
a
x
2
+
b
x
+
c
ax
2
+bx+c, the factored form is:
a
(
x
−
−
b
+
b
2
−
4
a
c
2
a
)
(
x
−
−
b
−
b
2
−
4
a
c
2
a
)
a(x−
2a
−b+
b
2
−4ac
)(x−
2a
−b−
b
2
−4ac
)
2 In this case,
a
=
3
a=3,
b
=
−
54
b=−54 and
c
=
343
c=343.
3
(
y
−
54
+
(
−
54
)
2
−
4
×
3
×
343
2
×
3
)
(
y
−
54
−
(
−
54
)
2
−
4
×
3
×
343
2
×
3
)
3(y−
2×3
54+
(−54)
2
−4×3×343
)(y−
2×3
54−
(−54)
2
−4×3×343
)
3 Simplify.
3
(
y
−
54
+
20
3
ı
6
)
(
y
−
54
−
20
3
ı
6
)
3(y−
6
54+20
3
)(y−
6
54−20
3
)
4 Factor out the common term
2
2.
3
(
y
−
2
(
27
+
10
3
ı
)
6
)
(
y
−
54
−
20
3
ı
6
)
3(y−
6
2(27+10
3
)
)(y−
6
54−20
3
)
5 Simplify
2
(
27
+
10
3
ı
)
6
6
2(27+10
3
)
to
27
+
10
3
ı
3
3
27+10
3
.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
54
−
20
3
ı
6
)
3(y−
3
27+10
3
)(y−
6
54−20
3
)
6 Factor out the common term
2
2.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
2
(
27
−
10
3
ı
)
6
)
3(y−
3
27+10
3
)(y−
6
2(27−10
3
)
)
7 Simplify
2
(
27
−
10
3
ı
)
6
6
2(27−10
3
)
to
27
−
10
3
ı
3
3
27−10
3
.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
27
−
10
3
ı
3
)
3(y−
3
27+10
3
)(y−
3
27−10
3
I hope this help you
