Karen will get mad because, Susan lost so much weight than her, she will call the police, rant to the manager of the program, cuss at Susan then get banned from the program and go to jail.

Step-by-step explanation:

That's what would REALLY happen, or did you want me to answer the math problem?

4 0

3 years ago

Ms. Blevins wants to survey a random sample of students at her middle school about the amount of homework assigned each night. W

NeTakaya

I think maybe 3) would make the most sense because she wants a random sample of students and the other options are specific on the type of students.

6 0

3 years ago

Researchers measured the bone mineral desnsity of the spines of 94 women who had taken teh drug CEE. The mean was 1.016 g/cm2, a

Valentin [98]

Answer:

The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{0.155}{\sqrt{94}} = 0.0310$

The lower end of the interval is the mean subtracted by M. So it is 1.016 - 0.0310 = 0.985 g/cm²

The upper end of the interval is the mean added to M. So it is 1.016 + 0.0310 = 1.047 g/cm²

The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².

6 0

3 years ago

14. Which of the following is the measure of ĐQRS?

GuDViN [60]

You’re going to need to add a picture to the problem it cannot be solved with just this information

5 0

3 years ago