All categories

3 years ago

PLEASE HELP Use the graph to find domain and range minimum maximum increasing decreasing X intercept Y intercept and find f(6)

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

4 0

Answer:

Answer is long, so Ill put it in the explanation.

Step-by-step explanation:

Domain: -∞ ≤ x ≤ ∞ (x goes infinitely in both directions)

Range: -∞ ≤ y ≤ 1 (infinite number of negative points, or going down, but stops at positive 1 going up)

y intercept: (0,0) (where the function meets the y-axis)

x-intercepts: (0,0) and (4,0) (where the function meets the x-axis)

minimum: -∞ ( doesnt have a lowest point, essentially there isnt one)

maximum: y = 1 (this is the highest point of the function)

f(6) = -3 (this is asking: when x = 6, what does y equal?)

This parabola is decreasing (it opens downwards)

You might be interested in

Correct answers only please!

Sergeu [11.5K]

Answer:

$ 5,150.00

Step-by-step explanation:

A = $ 5,150.00

A = P + I where

P (principal) = $ 5,000.00

I (interest) = $ 150.00

3 0

3 years ago

Whats the answer for 55.78 +4.6

Katarina [22]

60.38 is the answer to this

3 0

4 years ago

Read 2 more answers

Tanner made his father a quilt. The width is 6 5 /7 meters by 7 3/ 5 meters what is the area of the quilt?

pogonyaev

Answer:

51.0285714…

Step-by-step explanation:

you just multiply them together.

4 0

2 years ago

Read 2 more answers

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

3 0

3 years ago

If you have 36 coins. Some are quarters and some are nickels. The total is $4.80. How many quarters and nickels are there?

sergiy2304 [10]

15 quarters= $3.75
21 nickels =$1.05
______________
36 coins = $4.80

8 0

3 years ago

PLEASE HELP Use the graph to find domain and range minimum maximum increasing decreasing X intercept Y intercept and find f(6)￼

PLEASE HELP Use the graph to find domain and range minimum maximum increasing decreasing X intercept Y intercept and find f(6)