Answer:
yes (also the c.o.p would be 5)
Step-by-step explanation:
if you model this on a graph, it comes out proportional because its starts from the origin, and its a straight line with no curves.
Answer:
Hey there!
First, we want to find the radius of the circle, which equals the length of line segment AC.
Length of line segment AC, which we can find with the distance formula: 
, which is equal to 5.
The equation for a circle, is: 
, where (h, k) is the center of the circle, and r is the radius.
Although I don't know the center of the circle, I can tell you that it is either choice B or D, because the radius, 5, squared, is 25.
Hope this helps :) (And let me know if you edit the question)
3/8 is the correct answer
3) In Δ BDC
|DC|/|BC| = cos C
cos C= 16/17.89
C= cos⁻¹( 16/17.89)=26.57⁰
In triangle ABC:
x=180-(90+26.57)=63.43
x=63.43
2)
AB/BD= tan(70⁰), AB=BD*tan(70⁰)
AB/BC=tan(40⁰), AB=BC*tan(40⁰)
BD*tan(70⁰)=BC*tan(40⁰)
BD=BC-CD=BC - 15
(BC -15)*tan(70⁰)=BC*tan(40⁰)
BC*tan(70⁰) -15*tan(70⁰)= BC*tan(40⁰)
BC*tan(70⁰) - BC*tan(40⁰) = 15*tan(70⁰)
BC(tan(70⁰)-tan(40⁰))= 15*tan(70⁰)
BC = 15*tan(70⁰)/(tan(70⁰)-tan(40⁰)) = 21.60
BC=21.60
1) In a quadrilateral sum of angles =360⁰.
PQS=SQR=50⁰, because SQ bisects PQR.
Using Law of sine in ΔSRQ
SR/sin ∠SQR = SQ/sinR, SQ = SR * sinR/sin SQR = 3*sin30/sin50 =3.26
SQ=3.26 cm
ΔPQS:
cos PQS= PQ/SQ
PQ=SQ*cosPQS =3.26*cos 50⁰=2.09=2.1
PQ=2.1 cm
Answer:
B
Step-by-step explanation:
B has a slope of 7 while A has a slope of 6.
slope of B 14-7/2-1 = 7
A slope is y= mx+b and m is the slope. so 6.
