Answer:
The probability the student studies Art and
Biology is 0.2143.
Step-by-step explanation:
Denote the events as follows:
A = a students studies Art
B= a students studies Biology
The information provided is:
N = 42
n (An B) = 9
n (A' n B) = 10
n (A' n B') =7
Then the number of students who study Art
but not Biology is:
n(An B') = N -n (An B) -n (A' nB) - n (A'n B')
= 42 - 10 - 7 - 9
= 16
The number of students who study Art but
not Biology is 16.
Compute the probability the student studies
Art and Biology as follows:
P(ANB)
n(ANB)
= 0.2143
Thus, the probability the student studies Art
and Biology is 0.2143.
Answer: 87 m
Step-by-step explanation:
This problem can be solved by using a simple ratio and proportion.
The way you figure this out is::
Model = 12 m/ 1 cm = x/7.25 cm
Solve for x and you should receive this answer:
x = 87 m
hope I helped, best wishes to your future studies...
-a
5x10x1 electrical and electrical equipment for electrical
The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
<h3>
Answer:</h3>
unshaded area = 25(4 -π) in^2 ≈ 21.46 in^2
<h3>
Step-by-step explanation:</h3>
Each of the shaded circles has a diameter of (20 in)/4 = 5 in, which also is the width of the enclosing rectangle. Then each circle has a radius of 2.5 in, and an area of ...
A = πr^2 = π(2.5 in)^2 = 6.25π in^2
The four circles together have an area of ...
4A = 4·(6.25π in^2) = 25π in^2
The area of the rectangle is the product of its length and width:
A = LW = (20 in)(5 in) = 100 in^2
Since the circles are shaded, the unshaded area is the difference between the rectangle area and the total area of the four circles:
unshaded area = (100 in^2) - (25π in^2) = 25(4 -π) in^2 ≈ 21.46 in^2
