Question

Find the values of x and y

Answer 1

Answer:

x=18√6 , y=36√2

Step-by-step explanation:

${z}^{2} = 18 {}^{2} + 18 {}^{2} - 2(18)(18) \cos(90 ) \\ z = 18 \sqrt{2 } \\ \frac{x}{ \sin(60) } = \frac{z}{ \sin(30) } \\ x = 18 \sqrt{6} \\ \frac{y}{ \sin(90) } = \frac{z}{ \sin(30) } \\ y = 36 \sqrt{2}$