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GuDViN [60]
2 years ago
15

Find the values of x and y

Mathematics
1 answer:
arsen [322]2 years ago
7 0

Answer:

x=18√6 , y=36√2

Step-by-step explanation:

{z}^{2}  = 18 {}^{2}  + 18 {}^{2}  - 2(18)(18) \cos(90 )  \\ z = 18 \sqrt{2 }  \\  \frac{x}{ \sin(60) }  =  \frac{z}{ \sin(30) }  \\ x = 18 \sqrt{6}  \\  \frac{y}{ \sin(90) }  =  \frac{z}{ \sin(30) }  \\ y = 36 \sqrt{2}

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