Hello :
<span>√(4x+13) = 2x-1......(1)
note : if ( a=b) so (a² = b²)
if : (</span>√(4x+13) )²= (2x-1)² so : 4x+13 = 4x²-4x+1
4x²-8x-12 = 0
x²-2x-3 = 0
(x+1)(x-3) = 0
x+1 = 0 or x-3=0
x= -1 or x=3
if : x= -1 : <span>√(4(-1)+13) = 2(-1)-1
</span>√9 =-3 but √9 =3
3 = -3 impossible ( -1 is not solution of equation (1)
if : x = 3 : √(4(3)+13) = 2(3)-1
5 = 5 ( right) conclusion : one solution : 3
Answer:
10/6
Step-by-step explanation:
all you have to do is divide x2 or 5 in this case - x2 or -5 with y2 or 3 - y1 or 3 so it would be
(5--5)/(3--3)
and 2 negatives are a positive so it would turn to
5+5/3+3 or 10/6
please rate 5 stars i would really appreciate it
Answer:
could you do the whole thing
Step-by-step explanation:
x - y + 5z = 3 .... (1)
4x + z = 0
.......(2)
x + 3y + z = -9 .......(3)
From (2) z = -4x, Substitute for z in (1) and (3):-
x - y + 5(-4x) = 3
-19x + y = 3 ......(4)
x + 3y - 4x = -9
-3x + 3y = -9
- x + y = -3 .....(5)
Subtract:- (4) - (5) we get
-18x = 0
x = 0
So z = -4x = 0
Substituting for x and z in equation (3):-
3y = -9
y = -3
Answer is x = 0 , y = -3 and z = 0