Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
Answer:
the graph shift down 135 units
Step-by-step explanation:
when there is no fixing cost:
f(x)=12x-1400
when there is fixing cost (0ne time): 12x-(1400+135)
the graph shift down 135 units
The answer is d) 0 and 1.
Answer:
<span> (x + 6) • (x + 5) • (x - 2)
Is this what u were looking for? Sorry if not XDD
</span>
5y-30=-5y+30
add 30 to both sides
5y = -5y+60
add 5y to both sides
10y = 60
divide both sides by 10
y = 6
<em>hope this helps!</em>
