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viva [34]
3 years ago
9

The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 10.4degrees. If skyscraper B

is 1472 feet​ tall, how far apart are the two​ skyscrapers? Assume the bases of the two buildings are at the same elevation.
Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

  8020 feet

Step-by-step explanation:

The tangent relation can be used to answer this question, since it relates the sides of a right triangle to the acute angle.

 tan(elevation angle) = (1472 ft)/(distance between)

Then ...

  distance between = (1472 ft)/tan(10.4°) ≈ 8020 ft

The skyscrapers are 8020 feet apart.

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Answer: There will be 5 packages of small juice bottles and 3 packages of yogurt.

Step-by-step explanation:

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So, number of packages of each package of juice is given by

\frac{30}{6}\\\\=5

And number of packages of each package of yogurt is given by

\frac{30}{10}\\\\=3

So, there will be 5 packages of small juice bottles and 3 packages of yogurt.

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3 years ago
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3 years ago
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Kisachek [45]
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3 0
4 years ago
If the first term of the series is 30 and the 14th term is 95, what is the sum of all the terms of the series?
RideAnS [48]

Answer:

D)  S_{14} = 875.

Step-by-step explanation:

Given  : If the first term of the series is 30 and the 14th term is 95,

To find : what is the sum of all the terms of the series.

Solution : We have given

First term = 30 .

14 th term = 95.

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7 0
4 years ago
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