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OLga [1]
3 years ago
12

Find the area of the triangle

Mathematics
1 answer:
kupik [55]3 years ago
6 0
Area = 1/2 * base * height 
 = 1/2 * 20 * 6
 = 1/2 * 120
 = 60 ft^2
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Prove that: 16sin20.sin40.sin60.sin80=3​
olga nikolaevna [1]

to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3

6 0
3 years ago
Any sort of help is appreciated, ty
Semenov [28]
The answer would be 1952 because the display of flag makes a right triangle so we will use Pythagorean theorem in order to find the sides and the sides total is 244 according to theorem, so we multiply by 8 to get the 8 flag display.  <span />
8 0
3 years ago
According to a survey conducted by Deloitte in 2017, 0.46 of U.S. smartphone owners have made an effort to limit their phone use
Alexxandr [17]

Answer:

44.16 ; 4.88

Step-by-step explanation:

Recall :

Mean, μ = np

Sample size, n = 96

Sample proportion, p = 0.46

For the mean :

Mean, μ = 96 * 0.46

0.46 * 96 = 44.16

The standard deviation :

σ = √npq

q = 1 - p = 1 - 0.46 = 0.54

σ = √npq = √(96 * 0.46 * 0.54)

σ = √23.8464

σ = 4.88

7 0
3 years ago
Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one
gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0
3 years ago
Q = {1.7, 1.1, 1.4, 2.1, 2.3, s}. What is the absolute difference between the greatest and least possible values of the median o
Daniel [21]

Answer:

Absolute difference between the medians = 0.35

Step-by-step explanation:

After arranging Q in ascending order excluding s, we get

Q = {1.1, 1.4, 1.7, 2.1, 2.3}

Here, the median is 1.7 ( The middlemost value is the required median.)

Now, if s < 1.7,

Q= {1.1, s, 1.4, 1.7, 2.1, 2.3}

Now for the least value, median = 1.55

If s > 1.7,

Q = {1.1, 1.4, 1.7, 2.1, s, 2.3}

Now for the greatest value, median = 1.9

Absolute difference between the medians = |1.9 -1.55|

                                                                          = 0.35

6 0
3 years ago
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