2x+1/6y+2x
2x+1/6y+-2x=12+-2x
1/6y+-2x+13
Dive both sides by 1/6:
1/6y/1/6= -2x+13/1/6
y=-12x+78
The first set would be (x+1) (x+2) (x+3)
The second set to be 2x, 3x, 4x
The simplified part for last would be (7x/3)
U=2x+3, x=u/2-3/2
u^2+8u+11=0
u1=(-8+sqrt(64-44))/2=-4+sqrt(5)
u2=-4-sqrt(5)
x1=u1/2-3/2=-7/2+sqrt(5)/2
x2=u2-3/2=-7/2-sqrt(5)/2
Let's write out what we do know...
70% of the people are under 16 years old
From this information, we can infer that 30% of the people are 16 or older.
100%-70%=30%
1/3 of the people 16 or older are teachers. There are 21 teachers.
1/3 of 30% is 10%
1/3*.30=.10 or 10%
So 21 is 10% the total number of people at the fair.
![\frac{10}{100}= \frac{21}{x} 2100=10x 210=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B10%7D%7B100%7D%3D%20%5Cfrac%7B21%7D%7Bx%7D%202100%3D10x%20%20%20210%3Dx)
(I cross multiplied and then divided both sides by 10 to get x=210)
There are 210 people at the fair.
Answer:
Step-by-step explanation:
Get the perimeter of the each shape and add it all up to get the total fencing material required.
2 square flower beds = 2 x 4a = 8a
1 rectangular play ground = 2l + 2w
total fencing material = 8a + 2l + 2w