First you put (x+5) into the initial function wherever you see x so it becomes
(x+5)^2+3(x+5)-10=x^2+kx+30
(x^2+5x+25)+(3x+15)-10 simplified left side
x^2+8x+30 fully simplified left side
thus k=8
x^2+8x+30=0 to find 0s
-4 + 3.7416573867739i
<span>-4 - 3.7416573867739i
</span>these are the roots you find after using the quadratic formula
the second one is the smallest
5849 rounded to the nearest hundred
- The number '8' is located in the hundreds place
- Since there is a '4' in the tens place, it's telling number '8' to stay the same
5849 ⇒ 5800
2621 rounded to the nearest hundred
- The number '6' is located in the hundreds place
- Since there is a number '2' in the tens place, it's telling number '6' to stay the same
2621 ⇒ 2600
Answer: 5800 - 2600
To work out what the other side is that you times 12 to get to 24 you would do: 24 divided by 12 equals 2 therefore you would do 12 times 2 to get 24