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3 years ago

(3p+5)(2) simplified

1 answer:

8 0

Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10

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faust18 [17]

Answer:

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Step-by-step explanation:

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3 years ago

What is the unit rate that converts gallons to quarts?

BigorU [14]

Volume units quarts to gallons (fluid and dry) conversion factor is 0.25 (quart is 1/4 of an gallon). To find out how many gallons in quarts, multiply by the factor, or simply use the converter below. 1 Quart = 0.25 (1/4) Gallon [US, UK, Fluid or Dry] Quart and gallon are imperial and US customary volume measurement units. In US customary system, both units have different volume capacity for dry and fluid measurements but in imperial (UK), the volume is the same for both fluid and dry measurement.

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3 years ago

Read 2 more answers

What is -15x + 80 > 170

Korolek [52]

Answer:

Step-by-step explanation:

Value of x should be less than (-6).

x = { .......,-9,-8,-7}

For example:

-15*-7 +80 = 105+80 = 185 >170

3 0

3 years ago

You decide to buy some berries as a surprise for your aunt from the local farmer’s market. However, when you arrive, you see tha

Amanda [17]

Blackberries 1
blueberries 2
rasberries 3
strawberries 4
if you have to choose 1 of the 4 then your fraction is
(1/4)
1/4 = 25%
so the probability of you choosing the right one is 25%
i hope this is easy to understand and helps a lot

4 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago