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Helen [10]
2 years ago
7

(3p+5)(2) simplified

Mathematics
1 answer:
Vsevolod [243]2 years ago
8 0
Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10
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¿Cuántas soluciones tiene la ecuación 2 + 6 (x - 4) = 3x - 18 + 3x?
Elena-2011 [213]

Answer:

x is undefined

Step-by-step explanation:

2 + 6(x - 4) = 3x - 18 + 3x

Open the bracket

2 + 6x - 24 = 3x - 18 + 3x

collect the like terms

6x -3x - 3x = -18 +24 - 2

0x = 4

x = 4/0

x is undefined

3 0
3 years ago
Giving away points! <br> =D
Rzqust [24]

Answer:

Thanks you very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very very much for points

6 0
3 years ago
Read 2 more answers
Need help with all parts please show you work for each part
bezimeni [28]
Vinegar is the x or horizontal oil is the y or vertical
\frac{3}{2}  =  \frac{y}{x}  \\ 3x = 2y \\ y =  \frac{3}{2} x
the point represent the amount of vinegar and oil so for 1 tbsp vinegar you need 1.5tbsp oil
4 0
2 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
Why is 1 + (−5) equal to −4? (1 point)
Dafna11 [192]

I'm pretty sure it's D

Filler to post

7 0
3 years ago
Read 2 more answers
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