All categories

3 years ago

Which planet revolves slowly around the Sun, has rings, and is known for its Great Red Spot?

Mathematics

2 answers:

Gala2k [10]3 years ago

8 0

Answer:

Jupiter

Explanation:

Jupiter is the largest planet of the Solar system. It has rings and Great Red Spot. The rings are composed of very tiny ice and dust that they are not visible to naked eyes. The Great Red Spot is a giant storm which is existing past many years and it is so big that it can fit two Earths'. As it is farther from the Sun, it revolves slowly around it. It has a period of about 11.9 years.

tresset_1 [31]3 years ago

5 0

It’s a Jupiter hope this held you

You might be interested in

A bag has 9 marbles in it. 6 of the marbles are Red and 3 of the marbles are Green. What is the ratio probability of pulling a R

Nana76 [90]

Answer:

85%

6:9

Step-by-step explanation:

6 0

3 years ago

Write the equation that describes the line in slope-intercept form.

Thepotemich [5.8K]

Answer:

y = 2x+4

Step-by-step explanation:

slope (m) = 2

point (-1,2)

so,

b = 2-2×(-1) = 4

y = mx+b

or, y = 2x+4

5 0

3 years ago

Joseph is weaving a ceremonial Native American sash. The sash will be 8 feet long when it is completed. Joseph wants to add a di

Elan Coil [88]

Answer:

20 diamonds

Step-by-step explanation:

It is given that,

Length of the sash when it is completed = 8 feet

Joseph wants to add a diamond shape every 0.4 feet along the sash.

We need to find no of diamonds the sash have when it is completed. It can be calculated by dividing total length by 0.4 feet. As a result,

n = 8/0.4

n = 20

Hence, 20 diamonds the sash will have when it is completed

7 0

3 years ago

If x= 1/2-√3 , prove that x³-2x²-7x+5=3

prohojiy [21]

$x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5$

$=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3$

6 0

3 years ago

Solve for a: 1/4a-17=-15

MAXImum [283]

1/4a-17=-15
1/4a=-15+17
1/4a=2
(1/4*4)a=(2*4)
a=8

4 0

4 years ago