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serg [7]
2 years ago
8

Did the old version of the instrument triangle have a different sound because of the open corner and different triangle shape of

isosceles triangle, instead of the equilateral triangle shape used today?
Mathematics
1 answer:
eduard2 years ago
7 0
Yes the old version has different sounds
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5=a/2(b+c) <br><br> Solve for b
yaroslaw [1]

Answer:

b = \dfrac{a - 10c}{10}

Step-by-step explanation:

\begin{array}{rcl}5 & = & \dfrac{a}{2(b + c)}\\\\5& = & \dfrac{a}{2b + 2c}\\\\10b + 10c & = & a\\10b & = & a - 10 c\\b & = & \mathbf{\dfrac{a - 10c}{10}}\\\end{array}

8 0
2 years ago
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

#SPJ4

8 0
10 months ago
Stella invested $6,100 in an account paying an interest rate of 6 1/2%compounded
grandymaker [24]

Answer:

9662.3822

Step-by-step explanation:

4 0
2 years ago
Put these in order starting from the smallest<br> 6^2 3^4 2^9<br> 5^3
Levart [38]

Answer:

6^2, 3^4, 5^3, and 2^9

Step-by-step explanation:

6^2= 36

3^4= 81

5^3= 125

2^9= 512

4 0
3 years ago
Which of the following values would complete the ordered pair if the point is on the graph of f (x) = -3x + 2 ?
Scrat [10]

Answer: the y-coordinate that completes the point is 5.


Explanation:


An ordered pair (x, y) indicates the x-and-y coordinates of a general point, where x is the input value of a function and y is the output value.


The output value is y = f(x) and must be found applying the rule (function) to the given input value.


In this case the rulte is f(x) = - 3x + 2, and the input value, x,  is - 1 (the first value of the ordered pair).


This is the mathematical procedure:

  • x = - 1
  • f(x) = f (-1) = -3 (-1) + 2 = 3 + 2 = 5.
5 0
2 years ago
Read 2 more answers
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