Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.81 times.
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Answer:
the answer is true. it is a high level language
Answer:
11011011
00000000
Explanation:
10022011 cant be an answer because bits are composed of 0s and 1s
and 11100 is too small.
Java.lang is the answer you're looking for