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Zolol [24]
3 years ago
6

What causes the poles of the electromagnet in an audio speaker to repeatedly switch directions?

Computers and Technology
2 answers:
Sphinxa [80]3 years ago
8 0

Answer:

C. a current that rapidly switches direction

Explanation:

An audio speaker is an electronic device that converts electrical signals into sound energy (waves). The alternating current flowing into the audio speaker is typically used to generate sound waves.

Hence, what causes the poles of the electromagnet in an audio speaker to repeatedly switch directions is due to a current that rapidly switches direction. The electromagnet is placed in a position where it experiences a constant magnetic field as a result of the presence of a permanent magnet. Like every magnet, the electromagnet and the permanent magnet interact with each other; opposite sides attract while like sides attract. This interaction generates a force, causing the alternating current to constantly reverse the poles of the electromagnet in an audio speaker to repeatedly switch directions.

lozanna [386]3 years ago
8 0

Answer:

C. a current that rapidly switches direction

Explanation:

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Create a Java program with threads that looks through a vary large array (100,000,000 elements) to find the smallest number in t
olchik [2.2K]

Answer:

See explaination

Explanation:

import java.util.Random;

public class Sample{

static class MinMax implements Runnable{

int []arr;

int start,end,min,max;

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atOverride

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}

public static void main(String[] args) throws Exception{

long beginTime = System.nanoTime();

Random gen = new Random();

int n=100000000;

int[] data = new int[n]; //generate and fill random numbers

for(int i = 0; i < data.length; i++) {

data[i] = gen.nextInt()%1000000;

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long endTime = System.nanoTime();

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//-----------------------------------------

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System.out.println("Time using 1 thread " + (endTime - beginTime)/1000000000f + " seconds."); //print time taken

//-----------------------------------------

System.out.println("Using 2 thread");

m1=new MinMax(data,0,n/2);

MinMax m2=new MinMax(data,n/2+1,n-1);

t1=new Thread(m1);

Thread t2=new Thread(m2);

beginTime=System.nanoTime();

t1.start();

t2.start();

t1.join(0);

t2.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(m1.min,m2.min)+","+Math.max(m1.max,m2.max));

System.out.println("Time using 2 thread " + (endTime - beginTime)/1000000000f + " seconds.");

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System.out.println("Using 3 thread");

m1=new MinMax(data,0,n/3);

m2=new MinMax(data,n/3+1,2*n/3);

MinMax m3=new MinMax(data,2*n/3+1,n-1);

t1=new Thread(m1);

t2=new Thread(m2);

Thread t3=new Thread(m3);

beginTime=System.nanoTime();

t1.start();

t2.start();

t3.start();

t1.join(0);

t2.join(0);

t3.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(Math.min(m1.min,m2.min),m3.min)+","+Math.max(Math.max(m1.max,m2.max),m3.max));

System.out.println("Time using 3 thread " + (endTime - beginTime)/1000000000f + " seconds.");

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t4.start();

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t2.join(0);

t3.join(0);

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System.out.println("Time using 4 thread " + (endTime - beginTime)/1000000000f + " seconds.");

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Ganezh [65]

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a) true

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Answer:

The answer to this question is given below in the explanation section.

Explanation:

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Other options are not correct because:

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