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Viefleur [7K]
3 years ago
6

Need help checking my answers

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

Step-by-step explanation:

_______

Good evening ,

______________

Look at the photo below for the answer,

:)

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Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0
1 year ago
Porfavor necesito ayuda en esto.<br> Es para hoy :(
yan [13]

Answer:

17

Step-by-step explanation:

6 0
2 years ago
50 PTS<br> Please Make sure its easy to understand
kkurt [141]

Answer:

1) -95.

2) 15.

3) The conference center is on floor 5.

Step-by-step explanation:

1) Evaluating gives -52-30-13=-(52+30+13)=-(95)=-95.

2) Substituting gives x+27=(-12)+27=15.

3) After going 4 floors down, we are on level -4. After going 9 floors up to the desired room, we are on level -4+9=5. So the conference center is on floor 5.

3 0
3 years ago
Read 2 more answers
Determine whether the graph of the quadratic function y = –x^2 – 10x + 1 opens upward or downward. Explain.
REY [17]
C. If the first coefficient is negative, then the graph opens downwards
3 0
3 years ago
The diagram shows a sector of a circle radius 10cm
Yuki888 [10]

Answer:

\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}

Step-by-step explanation:

\text{Perimeter of the sector = Radius + arc length + radius}

\text{Radius = 10 cm}

\text{Perimeter of the sector = 10 + arc length + 10  }

 \text{Perimeter of the sector = 20 + arc length  }

\text{arc length   = (sector angle/ 360 ) * perimeter of the circle}

\text{Perimeter of a circle }=2\pi r

\text{sector angle} = 135

\text{arc length}   =  (135/ 360 ) * 2\pi (10)

= (3/8) 20\pi

= 15\pi /2

\text{Using  }\pi =3.14

= 15 * 3.14 /2

= 23.55

\text{Perimeter of the sector = 20  + 23.55}

= 43.55

= 43.6  cm

\text{perimeter of the sector  = 43.6  cm }

8 0
2 years ago
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