2 years ago

Anybody help please hm

Mathematics

1 answer:

Sati [7]2 years ago

4 0

The answer should be C

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Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

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2 years ago

Which is the value of 2c2d if c = 0.5 and d = 3? A. 0.15 B. 1.5 C.33 D. 6 E 15

aksik [14]

Answer:

The answer is D (6).

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2 years ago

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3 years ago

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Alexxx [7]

The answer would be c

7 0

2 years ago

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1200-5(3x+30)=600 show the steps to solve this problem

Romashka [77]

Answer:

x=+30

Step-by-step explanation:

1200-5(3x+30)=600

We move all terms to the left:

1200-5(3x+30)-(600)=0

We add all the numbers together, and all the variables

-5(3x+30)+600=0

We multiply parentheses

-15x-150+600=0

We add all the numbers together, and all the variables

-15x+450=0

We move all terms containing x to the left, all other terms to the right

-15x=-450

x=-450/-15

x=+30

3 0

3 years ago

Read 2 more answers

Anybody help please hm​

Anybody help please hm