Facto made chicken dish for dinner. She added a 10-ounce package of vegetables and 14-ounce package of rice to 40 ounces of chic
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Answer:
Part 1) Descending Rate = -2,000 ft/min
Part 2) Starting altitude value is 33,000 ft
Part 3) The linear equation for the plane's altitude (y) as a function of time (x) is:
Part 4) The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent
Step-by-step explanation:
Part 1)
The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):
Part 2)
When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft
Part 3)
We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b
by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:
with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:
Part 4)
The information that was not used to write the descent equation was the initial details about how long the plane traveled (4 hours) and for 1800 miles.
Answer:
Check the explanations
Step-by-step explanation:
According to given information, an instructor at a major research university occasionally teaches summer session and notices that that there are often students repeating the class. On the first day of class, she counts 105 students enrolled, of which 19 are repeating the class. The university enrolls 15,000 students.
Therefore the number of observation n 105 and enrolled x=19
1. An estimate of the population proportion repeating the class is given by:
c) 0.181.
Explanation:
19 --0.18090,181 n 105
2. The instructor wishes to estimate the proportion of students across campus who repeat a course during summer sessions and decides to do so on the basis of this class. Would you advise the instructor against it and why:
d) Yes, because this class is not a random sample of students.
3. The standard error for the estimated sample proportion is given by:
c) 0.0376.
Explanation:
SE
0.181 × (1-0.181) 105
0,0376 0.0376
4. A 95% confidence interval is given by:
c) 0.107, 0.255.
Explanation:
In order to determine the 95% confidence interval we follow the following step:
Where the z value is determined from the standard normal table as ~ 1.96
0.181 ± (1.96 × 0.0376)
0.181 ± 0.0737
Therefore the lower confidence interval is
LCI= 0.181- 0.0737
LCI= 0.107
Therefore the upper confidence interval is
UCI = 0.181 + 0.0737
UCI0.255
Therefore 95% confidence interval is
5. She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are:
d)
Explanation:
She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are defined on the basis of observation,
Null hypothesis as:
:p= 0.10
and alternative hypothesis as:
6. The test statistic for this hypothesis is given by:
c) 2.765.
Explanation:
In order to determine the z test statistics as:
Z=
0.181 - 0.10 0.10x (1-0.10)
=2.765
7. The P value for this test is:
c) 0.01>P>0.005 .
Explanation:
P value is calculated as:
P(Z > 2.765) 0.002845 for one tail test and
P(Z > 2.765) 0.005692 for two tail test.
8. Based on the p-value found:
b) we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%.
Explanation:
As the z observed is more than the tabulated z value at 95% as:
and also P value is less than the
Therefore we accept the alternative hypothesis and we may conclude that we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%.