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2 years ago

Complete the following statement.

Mathematics

2 answers:

allochka39001 [22]2 years ago

7 0

Answer:

Answers?

Step-by-step explanation:

Hopefully this is the correct answer i'm sorry if it's wrong.

dangina [55]2 years ago

3 0

Answer:

ukkkk

Step-by-step explanation:

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PLEASE ANSWER ASAP!!

Rufina [12.5K]

Answer:

The instantaneous rate of increase of f(x) at $x_{0} = 3$ is 3.
One possible equation of this line is y = 3x - 16.
The line is tangent to the graph of y = f(x). The slope of the line is the same as the instantaneous rate of increase of f(x) at $x_{0} = 3$ .

Step-by-step explanation:

$\begin{aligned}&\lim_{h\to 0}{\frac{f(3+h)-f(h)}{h}}\\ =&\lim_{h\to 0}\frac{1}{h} \cdot [(3^{3} + 3 \times 3^{2}h +3\times 3h^{2} + h^{3})- 4(3^{2} + 2\times 3h + h^{2}) + 2 \\[-1em] &\phantom{\lim_{h\to 0}\frac{1}{h}\cdot []} -(3^{3} -4\times 3^{2} + 2)]\\ = &\lim_{h \to 0}\frac{h^{3} + 5h^{2} +3h}{h}\\=& \lim_{h \to 0}{h^{2}} + \lim_{h \to 0}{5h} + \lim_{h\to 0}{3}\\ =& 3\end{aligned}$ .

$f(3) = 3^{3} - 4\times 3^{2} + 2 =-7$ .

In other words, the graph of y = f(x) passes through the point (3, -7) where $x = 3$ .

The point-slope form of a line in a cartesian plane is:

$y - y_0 = m (x - x_0)$ .

For this line,

$(3, -7)$ is the point on the line, while

$3$ is the slope of the line.

The equation of this line will thus be

$y - (-7) = 3(x - 3)$ .

That's equivalent to

$y = 3x - 16$ .

Refer to the diagram attached. The line touches the graph of y = f(x) at x = 3 without crossing it. The line here is thus a tangent to the graph of y = f(x) at x = 3. The slope of the line represents the instantaneous rate of increase of f(x) at $x_{0} = 3$ .

4 0

3 years ago

Determine the equation of the parabola whose graph is given below. Write your answer in General Form. A parabola on a coordinate

dimaraw [331]

The equation of parabola becomes y = -2/25(x-3)^2 + 4.

According to the statement

we have given a graph and from this graph we have to find the equation of parabola in the general form.

So,

we know that the equation of parabola in general form is

y = a(x-h)^2 +k - (1)

From the graph we have:

a point on the graph is (x,y) = (-2,2)

the vertex of the graph is (h,k) = (3,4)

Now, substitute these values in the equation number (1)

Then

y = a(x-h)^2 +k

2 = a(-2-3)^2 +4

2 = a(-5)^2 +4

2 = a(25) +4

25a = -2

a = -2/25.

Now put a = -2/25 and (h,k) = (3,4) in the equation(1).

Then

the equation of parabola becomes y = -2/25(x-3)^2 + 4

So, The equation of parabola becomes y = -2/25(x-3)^2 + 4.

Learn more about equation of parabola here brainly.com/question/4061870

#SPJ4

6 0

2 years ago

Evaluate 4 - 2(a2 – b2)2 when a = 3 and b = 2.

Anton [14]

Answer:

-46

Step-by-step explanation:

4 - 2(a^2 – b^2)^2 =

= 4 - 2(3^2 – 2^2)^2

= 4 - 2(9 - 4)^2

= 4 - 2(5)^2

= 4 - 2(25)

= 4 - 50

= -46

6 0

3 years ago

Read 2 more answers

2 please answer this question

Fittoniya [83]

B. End of the reconstruction.

4 0

3 years ago

Read 2 more answers

What is the gcf for 84 and 54

solmaris [256]

Your answer for the greatest common factor is 6

3 0

2 years ago