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klemol [59]
3 years ago
6

Find a polar equation for the curve given by the cartesian equation y = 2x 2 .

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0

The first has no r , only 0 since it is a straight line.

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Express x3 + 4x2 – 45x in factored form.
kolbaska11 [484]
15 is the answer it is correct can
4 0
3 years ago
This year consumers purchased 7,234,267,990 bottles of water. Last year consumers purchased 2,000,900,999 bottles of water. Whic
torisob [31]

Answer:

B. 9,000,000,000

Step-by-step explanation:

From the given information:

We are to determine the best estimate of the number of bottles sold this year and last year.

The best estimate means rounding up to the nearest whole number.

Given that:

7,234,267,990 bottles of water were purchased this year

2,000,900,999  bottles of water were purchased last year

The estimate of the bottles sold this year and last year from the above value is:

= 7,000,000,000 + 2,000,000,000

= 9,000,000,000

4 0
3 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
Which transformation of triangle T will produce triangle U?
Bezzdna [24]

Answer:A

Step-by-step explanation:

6 0
3 years ago
I need help with this ​
LuckyWell [14K]

Answer:

1st - Yes ; 2nd - Yes ; 3rd - Yes ; 4th - No

Step-by-step explanation:

8 0
3 years ago
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