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maw [93]
3 years ago
15

What is the relationship between the circumference of a circle and its diameter?

Mathematics
2 answers:
Vilka [71]3 years ago
7 0

its a for a +

Step-by-step explanation:

Hatshy [7]3 years ago
5 0
The answer is A to the question
You might be interested in
What are the slope and y intercept of the line described by the equation y=-4/5x -10
rodikova [14]

The slope is -\frac{4}{5} and y-intercept is -10

Step-by-step explanation:

Given equation is:

y = -\frac{4}{5}x-10

The given equation is in slope-intercept form

General form of slope-intercept form of equation of line is:

y = mx+b

Here

m is the slope

b is the y-intercept

So,

comparing both equation we get

The coefficients of x

m = -\frac{4}{5}

And

b = -10

Hence,

The slope is -\frac{4}{5} and y-intercept is -10

Keywords: Slope, equation of line

Learn more about equation of line at:

  • brainly.com/question/7419893
  • brainly.com/question/730852

#LearnwithBrainly

7 0
3 years ago
PLEASE HELP I WILL MARK BRAINLEST PLEASE!!!!! 11 bounus points if u get it correct
Ratling [72]

Answer:

the answer is -1.8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
* PLEASE HELP *
saul85 [17]

Answer:

C is the only correct answer

4 0
2 years ago
A triangle has a base of 15 feet and a height of 9 feet. What is the area of the triangle? Label the figure. Write the formula,
bazaltina [42]

Answer:

135...................

8 0
3 years ago
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°
djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, \angle ABN is 37°. We can see from the diagram that \angle ABC would be 180-37= 143°.

Also, the new bearing is N 25°E. So, \angle BCA would be 25°.

Now we can find \angle BAC. As the sum of the internal angle of a triangle is 180°.

\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is AC=x

We can apply the sine rule now.

\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0
3 years ago
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