Answer:
They roam 958 acres combined.
Step-by-step explanation:
612 + 346
= 958
I = $ 1,200,000.00
Equation:
I = Prt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year,
then, solving our equation
I = 1000000 × 0.03 × 40 = 1200000
I = $ 1,200,000.00
The simple interest accumulated
on a principal of $ 1,000,000.00
at a rate of 3% per year
for 40 years is $ 1,200,000.00.
The inequality to determine the number of runs per inning, p Kim's team could have scored is; 4r + 6 > 17
<h3>How to write an Inequality?</h3>
Let r represent the number of runs per inning. Thus for 4 innings, we have 4r.
The team already has 6 runs. Now add the additional runs to this to get;
4r + 6
The team wants to score more than the other team, this means they need more than 17 and so the inequality required is;
4r + 6 > 17
Subtract 6 from each side to get;
4r + 6 - 6 > 17 - 6
4r > 11
Divide both sides by 4 to get:
r > 2.75
Approximating to a whole number gives;
r > 3
Read more about writing inequalities at; brainly.com/question/25275758
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Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:

Compute the probability that a person does not have the disease as follows:

The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:


Thus, the probability of the test indicating that the person does not have the disease is 0.1452.