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Mariulka [41]
3 years ago
5

Which condition is a result of using an anaerobic digester?

Biology
2 answers:
Elan Coil [88]3 years ago
3 0
The condition which is a result of using an anaerobic digester is B) increase in land fertility due to the addition of the nitrogen and phosphorous byproduct. 
musickatia [10]3 years ago
3 0

Answer: b. increase in land fertility due to the addition of the nitrogen and phosphorous byproduct

Anaerobic digestion is a process by which microorganisms breaks down complex biodegradable materials into simpler products, in the absence of oxygen. The anaerobic digesters hold the manure or any another form of organic matter which needs to be decomposed off in the absence of oxygen allows the extensive growth of microbes in it. The partially digested biodegradable waste in the form of slurry can be distributed over an agricultural land which can be useful in adding up the organic matter in the form of organic nitrogen and organic phosphorus produced as byproducts. The organic nitrogen and organic phosphorus are important elements are important for plant growth and development. Hence, the waste will increase the fertility of the land.  

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The question is incomplete. Here is the complete question.

You are studying a population of ground squirrels. You trap 100 individuals and find 9 that have a light colored coat and the rest have a dark coat. You know that light coat color is recessive in ground squirrels. What is the allele frequency for the light coat allele  and the dark coat allele? How many of the dark coated individuals do you expect to be heterozygotes at the coat color gene? Assume the population is at H-W equilibrium.

Answer: Allele frequency for light coat: q = 0.3;

              Allele frequency for dark coat: p = 0.7;

             There will be 42 heterozygote;

Explanation: A population in H-W equilibrium is a population which doesn't change from one generation to the next if there are no disturbing factors, as migration or mutation.

It follows the equation: p^{2}+2pq+q^{2}=1.

p represents the frequency of the dominant allele;

q represents the frequency of the recessive allele;

2pq represents heterozygote individuals;

The sum of frequencies of both alleles must be 1, i.e.: p+q=1

For the population of squirrels:

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q^{2} = \frac{9}{100}

q = \sqrt{\frac{9}{100}}

q = 0.3

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p+q=1

p=1-q

p=1-0.3

p = 0.7

  • Frequency of heterozygote

2pq = 2*0.7*0.3 = 0.42

In a population of 100 individuals: 0.42*100 = 42

The allele frequency for the light coat is 0.3; for the dark coat is 0.7.

It is expected to have 42 heterozygote individuals in this population.

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