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3 years ago

Six less than a number squared ALGEBRAIC EXPRESSION HELP

2 answers:

7 0

Hey!
So it is 6 less than a number squared. a number will be represented as x. So we know that there is a 6 and an x^2. What we need to figure out is whether it is 6-x^2 or x^2 - 6
well its asking 6 less than a number squared which means after a number is squared subtract 6.
so the answer is x^2 - 6
hope this helps!

juin [17]3 years ago

6 0

Call the number to be squared = x
Then the expression is x^2 - 6

If there is more to the question, please put it in a comment and I'll edit this.

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Complete the expressions that would make them a perfect square trinomial.

kirza4 [7]

Answer:

a) 16

b) 100

c) 64

d) $\frac{81}{4}$ [/tex]

Step-by-step explanation:

Perfect square trinomial:

A perfect square trinomial has the following format:

$(x \pm a)^2 = x^2 \pm 2ax + a^2$

x² – 8x

$x^2 - 8x = x^2 - 2ax$

So 2a = 8, a = 4. Then

$a^2 = 4^2 = 16$

The perfect square trinomial is $x^2 - 8x + 16$

b. x2 + 20x +

2a = 20, so a = 10

$a^2 = 10^2 = 100$

The perfect square trinomial is $x^2 + 20x + 100$

x² – 16x +

2a = -16, so a = -8.

$a^2 = (-8)^2 = 64$

The perfect square trinomial is $x^2 - 16x + 64$

d. x2 + 9x +

$2a = 9$ , so $a = \frac{9}{2}$

$a^2 = (\frac{9}{2})^2 = \frac{81}{4}$

The perfect square trinomial is $x^2 + 9x + \frac{81}{4}$ [/tex]

6 0

3 years ago

SOMEONE HELP ME plzzzzzzzzzzzzzz

Leona [35]

To find the answer you have to find the area of the fountain using A= pi r^2.
=(3.14)(64)
=200.96

Then you have to find the area of the big circle.
=(3.14)(11^2)
=379.94

Then subtract them both (379.94-200.96) and you get the answer 178.98 which can be rounded to 179 aka A.

3 0

3 years ago

Factorize 5n-mp-5n+pn

Mamont248 [21]

We are firstly gonna start with simplifying the expression.

1) So we have a 5n and a - 5n and if we add it together, we get nothing. So it is now -mp + pn or pn - mp

2) Now there is a p in the expression so we can multiply n and -m by p. Now have p(n-m)

So the answer is p(n-m)

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

7 0