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3 years ago

Find the compound area of the following shape. Do not include units in your answer. *

Mathematics

1 answer:

qaws [65]3 years ago

6 0

Answer:

357_²

Step-by-step explanation:

find the area of the cut out triangle

20 * 21 = 240

240/2 = 210

find the over all area

21 * 27 = 567

subtract the missing piece

567 - 210 = 357

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OP = ?<br> A)3<br> B) 3.5<br> C) 4

Aleksandr [31]

OP = 4 because its a radius of the smaller circle which has a radius of 4 and all radii of the same circle are the same length.

C) 4

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3 years ago

Read 2 more answers

(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate

kirill115 [55]

(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

$S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}$

So yes, you enter S' = 0.54 - (9S/1060)

(c)

$\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\ \Rightarrow\ C = -\frac{1}{9} \ln 572.4$

$-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)$

But only (+) satisfies $S(0) = 0$

$S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}$

Enter in S = 63.6 - 63.6 * e^(-9t/1060)

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3 years ago

What type of graph would have the title, "Mile Time of a Typical 5th Grade Student

nevsk [136]

Bar graph or plot graph

5 0

3 years ago

Can you please do 1 to 4

kodGreya [7K]

1 to 4; 1 for every 4; 1/4;

3 0

4 years ago

A square has a side length of 2.5 meters. What is the largest radius of the largest that can fit inside the square.

Oksanka [162]

The largest radius of the circle that can fit inside the given square is 1.25 meters

Step-by-step explanation:

Step 1 :

Given,

the side of the square = 2.5 meters

We need to determine the largest radius of the circle that can fit inside this square

Step 2 :

The diameter of the largest circle that can fit inside a square will be equal to length of given square's side.

So here the largest diameter will be 2.5 meters

Therefore the radius = diameter ÷ 2 = 2.5 ÷ 2 = 1.25 meters

Step 3 :

Answer :

The largest radius of the circle that can fit inside the given square is 1.25 meters

6 0

3 years ago