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hodyreva [135]
3 years ago
6

One evening in snowed in several towns the number of inches of snow received are shown in the list below

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

Please find the required line chart created with MS Excel

Step-by-step explanation:

Question:

The given data are;

3/4, 1 1/2, 2, 1 1/4, 3/4, 2, 1 1/2, 1 1/4, 1 1/2, 1/2, 1

In the question, it is required to create a line plot to represent the data

The given data can be sorted in ascending order in decimal form as follows;

0.5, 0.75, 0.75, 1, 1.25, 1.25, 1.5, 1.5, 1.5, 2

The line chart created with MS Excel is attached.

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I honestly need help on this...I tried to work it out but I just don’t know where to start...
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

1) The sum of angles on a straight line is 180 degrees. Therefore

75 + a + 70 = 180

145 + a = 180

a = 180 - 145 = 35 degrees

2) Sum of the angles in a triangle is 180 degrees. Therefore,

a + b + 95 = 180

35 + b + 95 = 180

130 + b = 180

b = 180 - 130 = 50 degrees

3) c + 95 = 180 degrees (sum of angles on a straight line).

c = 180 - 95 = 85 degrees

4) 70 + c + d = 180 degrees

70 + 85 + d = 180

155 + d = 180

d = 180 - 155 = 25 degrees

5) e = 75 degrees

6) f + e + 75 = 180 degrees

f + 75 + 75 = 180

f + 150 = 180

f = 180 - 150 = 30 degrees

4 0
3 years ago
Linear Algebra question! Please help!
kozerog [31]

Answers:

  1. false
  2. false
  3. true
  4. false
  5. True

==================================================

Explanation:

Problem 1

This is false because the A and B should swap places. It should be (AB)^{-1} = B^{-1}A^{-1}.

The short proof is to multiply AB with its inverse (AB)^{-1}  and we get: (AB)*(AB)^{-1} = (AB)*(B^{-1}A^{-1}) = A(B*B^{-1})*A^{-1} = A*A^{-1} = I

The fact we get the identity matrix proves that we have the proper order at this point. The swap happens so that B matches up its corresponding inverse B^{-1} and the two cancel each other out.

Keep in mind matrix multiplication is <u>not</u> commutative. So AB is not the same as BA.

-------------------------

Problem 2

This statement is true if and only if AB = BA

(A+B)^2 = (A+B)(A+B)

(A+B)^2 = A(A+B) + B(A+B)

(A+B)^2 = A^2 + AB + BA + B^2

(A+B)^2 = A^2 + 2AB + B^2 ... only works if AB = BA

However, in most general settings, matrix multiplication is <u>not</u> commutative. The order is important when multiplying most two matrices. Only for special circumstances is when AB = BA going to happen. In general,  AB = BA is false which is why statement two breaks down and is false in general.

-------------------------

Problem 3

This statement is true.

If A and B are invertible, then so is AB.

This is because both A^{-1} and B^{-1} are known to exist (otherwise A and B wouldn't be invertible) and we can use the rule mentioned in problem 1. Make sure to swap the terms of course.

Or you can use a determinant argument to prove the claim

det(A*B) = det(A)*det(B)

Since A and B are invertible, their determinants det(A) and det(B) are nonzero which makes the right hand side nonzero. Therefore det(A*B) is nonzero and AB has an inverse.

So if we have two invertible matrices, then their product is also invertible. This idea can be scaled up to include things like A^4*B^3 being also invertible.

If you wanted, you can carefully go through it like this:

  1. If A and B are invertible, then so is AB
  2. If A and AB are invertible, then so is A*AB = A^2B
  3. If A and A^2B are invertible, then so is A*A^2B = A^3B

and so on until you build up to A^4*B^3. Therefore, we can conclude that A^m*B^n is also invertible. Be careful about the order of multiplying the matrices. Something like A*AB is different from AB*A, the first of which is useful while the second is not.

So this is why statement 3 is true.

-------------------------

Problem 4

This is false. Possibly a quick counter-example is to consider these two matrices

A = \begin{bmatrix}1 & 0\\0 & 1\end{bmatrix} \text{ and } B = \begin{bmatrix}-1 & 0\\0 & -1\end{bmatrix}

both of which are invertible since their determinant is nonzero (recall the determinant of a diagonal matrix is simply the product along the diagonal entries). So it's not too hard to show that the determinant of each is 1, and each matrix shown is invertible.

However, adding those two mentioned matrices gets us the 2x2 zero matrix, which is a matrix of nothing but zeros. Clearly the zero matrix has determinant zero and is therefore not invertible.

There are some cases when A+B may be invertible, but it's not true in general.

-------------------------

Problem 5

This is true because each A pairs up with an A^{-1} to cancel out (similar what happened with problem 1). For more info, check out the concept of diagonalization.

5 0
2 years ago
a rectangular prism has a volume of 1374.28 cubic inches.The prism is 9.4 inches wide and 17.2 inches long.What is the height of
NISA [10]
The volume V of a prism can be found by:
The volume of a rectangular prism can be found through:
V=lwh
Where l is the length, w is the width, and h is the height.

The height can be found by rearranging the equation to:
h= \frac{V}{wl}

Take the volume (1374.28) and divide it by the length times the width (9.4*17.2=161.68).
1374.28/161.68= 8.5 inches is the height of the prism.
6 0
3 years ago
The accompanying stem-and-leaf plot represents Kiko's test scores this year. What is the median score for this set of data?
worty [1.4K]

Answer: 80

Write down all the values and cross out until you get to the middle, since there are 2 values, find the mean, which would be 80

6 0
3 years ago
Don’t judge :| <br> help pls:p
Paha777 [63]

Answer:

5x−4y

Step-by-step explanation:

:D

6 0
2 years ago
Read 2 more answers
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