4 years ago

Which of the following is true of vertex-edge graphs?

1 answer:

Finger [1]4 years ago

8 0

The answer would be 2 they can all be solved

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Vilka [71]

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3 years ago

Alika [10]

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The distribution of sample means will form a normal distribution

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3 years ago

AVprozaik [17]

Answer:

$\sqrt{37}$ units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.

We know the formula of length of perpendicular from a point $(x_{1}, y_{1} )$ to the straight line ax + by + c = 0 is given by

$\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}$

Therefore, in our case the perpendicular distance is

$\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}$ units. (Answer)

6 0

4 years ago

Olegator [25]

X^2 + 6x + 9
x 3
x 3

(x+3) (x+3)

x^2 + 3x + 3x + 9 (FOIL method)
x^2 + 6x + 9 (true)

your answer is 9 as the constant

hope this helps

8 0

4 years ago

user100 [1]

Answer:

143

Step-by-step explanation:

8 0

3 years ago