Answer:
w = 13 m
l = 32
Step-by-step explanation:
let 'w' = width
let '2w+6' = length
P = 2l + 2w
90 = 2(2w+6) + 2w
90 = 4w + 12 + 2w
90 = 6w + 12
78 = 6w
w = 13
length = 2(13) + 6 → 32
l = 32
check:
2(13) + 2(32) should equal 90
26 + 64 = 90
90 = 90 checks out
60,000 is the correct answer
Answer:
see explanation
Step-by-step explanation:
(4)
consider the left side
factor the numerator
cosx - cos³x = cosx(1 - cos²x)
cancel sinx on numerator/denominator
= cosxsinx =right side ⇒ verified
(5)
Consider the left side
expand the factors
(1 + cotΘ)² + (1 - cotΘ)²
= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ
= 2 + 2cot²Θ
= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ
= 2cosec²Θ = right side ⇒ verified
(6)
Consider the left side
the denominator simplifies to
cosxtanx = cosx × = sinx
= sinx( + )
= +
= tanx + 1 = right side ⇒ verified
Answer:
The worth of truck is $2,201 more after 2 years than after 3 years.
Step-by-step explanation:
Given:
The value of truck is depreciate per year using above formula.
We need to find how much more worth of truck after 2 years than 3 years.
First we find the worth of truck after 2 years, put x=2 into formula
The worth of truck after 2 years would be $27,508
Now we find the worth of truck after 3 years, put x=3 into formula
The worth of truck after 2 years would be $25,307.36
Now we find difference of both value.
Difference = 27508-25307.36 = $2,201
Hence, The worth of truck is $2,201 more after 2 years than after 3 years.
If the answers are in the standard form of a line then it would be -x + (-3x) = -5y. This is because the standard form of a line is written as Ax + Bx = Cy