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4 years ago

How do you make 8 out of 8, 12, 2, 7, 4

Mathematics

1 answer:

muminat4 years ago

3 0

Answer:

8 = 2 ( (8-7) + (12/4) )

Step-by-step explanation:

2 ( (8-7) + (12/4) )

2 ( ( 1 ) + ( 3 ) )

2 ( 4 ) = 8

It takes a bit of thinking and writing it out on paper to come up with an equation that works and you should definitely practice it so it becomes easier

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Consider the following scenario: There are three advertisers A, B, and C A bids on query x, B bids on x and y, and C bids on x,

yuradex [85]

Answer:

A A A B B B C C C

Step-by-step explanation:

We have the Greedy algorithm, the solution at any time is considered an optimal algorithm.

In our case the sequence is x x x y y y z z z

In addition to the Greedy algorithm, the first advertiser chooses their choice without considering the minimum methods.

Now we must consider the worst case of greedy algorithm so we must suppose that it starts from advertiser C, then B and followed by A.

Therefore the worst option would come being:

C C C B B B, in addition that A cannot bid for any query.

Which means that the sequence of the balanced algorithm will be A A A B B B C C C

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3 years ago

If the circumference of a circle measures 3/4 π cm, what is the area of the circle in terms of π?

Vinil7 [7]

$\bf \textit{circumference of a circle}\\\\
C=2\pi r~~
\begin{cases}
r=radius\\
-----\\
C=\frac{3\pi }{4}
\end{cases}\implies \cfrac{3\pi }{4}=2\pi r
\\\\\\
\cfrac{3\pi }{4(2\pi )}=r\implies 
\boxed{\cfrac{3}{8}=r}\\\\
-------------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad \qquad \implies A=\pi \left( \boxed{\frac{3}{8}} \right)^2\implies A=\pi \left( \cfrac{3^2}{8^2} \right)
\\\\\\
A=\cfrac{9\pi }{64}$

5 0

4 years ago

Ummm... I dont know how to do this: raise the quotient of s and r to the 3rd power

denis23 [38]

Step-by-step explanation:

Quotient of s and r is s/r

s/r to the 3rd power = (s/r)^3

6 0

3 years ago

Cual es el valor de x en<br> 3x-15=2x+20

erastova [34]

Answer:

x=35

Step-by-step explanation:

7 0

3 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

3 years ago