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Furkat [3]
3 years ago
9

Can someone help with these 3 questions, they are in the pictures!

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0

Question One
y = v - 1/2 g t^2   Subtract v from both sides.
y - v = - 1/2 gt^2  Multiply both sides by - 1
-(y - v) =  1/2gt^2 Remove the brackets.
v - y = 1/2 gt^2 Divide by g
(v - y)/g = 1/2 t^2 Multiply by 2 on both sides
2(v - y)/g = t^2 Move the 2 to the denominator on the left.
(v - y) / 0.5g = t^2 Take the square root of both sides.
sqrt [ (v - y) / 0.5g ] = t 

Answer: B or second one down <<<<<<<

Question Two  
There are no minuses in the answer. That eliminates 2 and 3
km^2 - c = n   Add c to both sides.
km^2 = c + n  divide both sides by k
m^2 = [c + n]/k  Take the square root of m^2
m = sqrt [(c + n)/k]

Answer A or the first one.

Problem 3
This is an estimation question. One value of x is <0 the other > 0
The two graphs cross when x = a bit over 2 and x < about - 5
The answer is C 2.1 and - 5.1 about.

Answer: 2.1 and -5.1 
Answer: C <<<<<<<<<

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Volunteers helped clean up 8.2 kg of trash in one neighborhood and 11 1/2 kg in another. They sent 1 1/4 kg to be recycled and t
Ivan

Answer: 18.45\ kg or 18\frac{9}{20}\ kg

Step-by-step explanation:

We can convert from mixed numbers to decimal numbers:

11\frac{1}{2}\ kg=(11+0.5)\ kg=11.5\ kg\\\\1\frac{1}{4}\ kg=(1+0.25)\ kg=1.25\ kg

Since they cleaned up 8.2 kilograms of trash in one neighborhood and 11.5 kilograms in another neighborhood, the total trash they cleaned up was:

Total=8.2\ kg+11.5\ kg\\\\Total=19.7\ kg

We know that they sent 1.25 kilograms to be recycled. Then, in order to calculate how many kilograms of trash they threw away, we must subtract the total kilograms of trash they cleaned up and the kilograms they sent to be recycled.

Then:

19.7\ kg-1.25\ kg=18.45\ kg or 18\frac{9}{20}\ kg

8 0
3 years ago
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The graph below shows a system of equations: Draw a line labeled y equals minus x plus 5 by joining the ordered pairs 0, 5 and 5
Montano1993 [528]

Answer:

The x-coordinate of the solution is x=3

Step-by-step explanation:

we have

y=-x+5 ------> equation A

y=x-1 ------> equation B

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Substitute equation B in equation A and solve for x

x-1=-x+5

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y=x-1  ------> y=3-1=2

The solution of the system of equations is the point (3,2)

therefore

The x-coordinate of the solution is x=3

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Step-by-step explanation:

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