The function, g(x), has a constant rate of change and will increase at a faster rate than the function f(x) for all the values of x.
Given:
g(x) = 5/2 x -3 ..... (1)
f(x) = - 3.5 at x = 0
So, putting the value of x=0 in equation (1) for comparison. We get,
g(x) at x = 0
=> g(x) = 5/2 x (0) - 3
=> g(x) = -3
In this value of x function g(x) is faster than function f(x) having a value equal to -3.5.
Similarly, put x = 1 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (1) - 3
=> g(x) = (5-6)/2
=> g(x) = -1/2
In this value of x function g(x) is faster than function f(x) having a value equal to -1.
Similarly, put x = 2 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (2) - 3
=> g(x) = (5-3)
=> g(x) = 2
In this value of x function g(x) is faster than function f(x) having a value equal to 1.5.
Similarly, put x = 3 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (3) - 3
=> g(x) = (15/2 - 3)
=> g(x) = 7.5 - 3
=> g(x) = 4.5
In this value of x function g(x) is faster than function f(x) having a value equal to 4.
Therefore, for all values of x function g(x) is faster than function f(x).
function f(x).
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Answer:
Rational
Step-by-step explanation:
-9 is rational because 9 is a perfect square and all perfect squares are rational.
Answer:
Step-by-step explanation:
To analyse a graph you are meant to determine a general trend, relating the results of an experiment to the hypothesis as well as to form. For example you look at all the values in a line graph and you are yo predict one you are to find its common increase or decrease.
If all possible vertical lines will only cross the relation in one place, then the relation is a function.This works because if a vertical line crosses a relation in more than one place it means that there must be two y values corresponding to one x value in that relation.
Answer:
14a + 20
Step-by-step explanation:
8(a + 2) + 2(2 + 3a)
expand the bracket
8a + (8*2) + (2*2) + (2*3a)
8a + 16 + 4 + 6a
bring like terms together
8a + 6a + 16 + 4
14a + 20
Answer:
1.7 units
Explanation:
The length of an arc is calculated using the formula below:
Substitute the given values of θ and r:
The length of the arc is 1.7 units.
