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cluponka [151]
2 years ago
5

When you roll a dice 2 times what is the probability of rolling a pair of 1’s

Mathematics
1 answer:
Mashutka [201]2 years ago
3 0

Answer:

1/6

Step-by-step explanation:

Probability= no. of possible outcomes÷ no. of total outcomes

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The sum of two consecutive integers is 75. Find the number
Luba_88 [7]

Divide 75 by 2:

75 / 2 = 37.5

Now you need the whole number below 37.5 and the whole number above 37.5:

37 + 38 = 75

The numbers are 37 and 38

4 0
3 years ago
PLEASE HELP!!!!!<br> Combine the like terms to create an equivalent expression. 8k+5k
horsena [70]

Answer:

13k

Step-by-step explanation:

Given: 8k+5k

Finding the equivalent expression.

We know the rule of addition is that adding two positive integers will give positive result or sum.

Now, lets find the equivalent expression of 8k+5k.

∴ 8k+5k= 13k

Hence, the required equivalent expression is 13k.

3 0
3 years ago
Simply the expression
____ [38]

Answer:

-63+14x

Step-by-step explanation:

7(-9+2x)=7(-9)+7(2x)=-63+14x

8 0
1 year ago
PLEASE HELP! I'LL GIVE BRAINLIEST!!!!!!!
daser333 [38]

Answer:

1.6x10^-18 gram

Step-by-step explanation:

(5.3 x 10⁻²³ gram/molecule) x (20,000 molecule)

= (5.3 x 10⁻²³ x 2 x 10⁴) gram

= (10.6 x 10⁻²³⁺⁴) gram

= (1.06 x 10⁻²³⁺⁵) gram

= 1.06 x 10⁻¹⁸ gram

We need to find the mass of 20,000 molecules of oxygen. It can be calculated using unitary method. Here, we can multiply 20,000 molecules  by the mass of one oxygen molecule.

7 0
3 years ago
The fourth term in an arithmetic sequence is 18 and the seventh term is 39. If the first term is a1 , which is an equation for t
evablogger [386]

Answer:

<h2>            aₙ = 7n - 10</h2>

Step-by-step explanation:

The nth term:  a_n=a_1+d(n-1)

So:

    a₄ = a₁ + 3d

18 =  a₁ + 3d   ⇒   3d =  18 - a₁

    a₇ = a₁ + 6d

39 = a₁ + 6d

39 = a₁ + 2(18 - a₁)

39 = a₁ + 36 - 2a₁

39 = 36 - a₁

a₁ = -3

3d = 18 - (-3)

3d = 21

d = 7

So the nth term:

                            a_n = -3 + 7(n-1)\\\\a_n=-3 +7n - 7\\\\a_n = 7n - 10

8 0
3 years ago
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