Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
Answer will be D. Absolute value can never be negative.
Which group of numbers is listed from least to greatest? -8, |-5|, -4, |3|, 6 |-6|, -4, |-2|, -1, 0 -4, |-2|, |3|, 5, |-7| -6, |
Anika [276]
I can’t help you because i can’t distinguish the groups
The second answer is correct. On the paper, CD are in the same spots as XY, and so forth for the other segments.
