Answer:
Explanation:
a. In this scenario, the best solution would have an Object of Traditional Books, CD, Music, Bookstore and Customer.
b. All five objects would be able to be called by the main program loop and the Customer Object would call upon and use either the Books or CD object, While the Bookstore object would call upon all of the other objects.
c. Both the Bookstore object and Customer object will "have" other objects as the Bookstore needs to hold information on every Book or CD in the Inventory. While the Customer object would call upon the Book and CD object that they are purchasing.
d. The Music Object will extend the CD object and use information on the CD object as its parent class.
e. Since the Music Object extends the CD object it is also considered a CD since it is in CD format like the Books on CD and therefore is both objects.
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
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