Find three numbers whose sum is 6 and whose sum of squares is a minimum.
1 answer:
Números que suman 6:
3 + 2 + 1 = 6=> 3^2 + 2^2 + 1^2 = 9 + 4 + 1 = 14
4 + 3 - 1 = 6 => 4^2 + 3^2 + (-1)^2 = 16 + 9 + 1 = 26 => do not use negative numbers, because that will increase the other numbers.
5 + 1 + 0 = 6 => 5^2 + 1 + 0 = 25 + 1 + 0 = 26
4 + 2 + 0 = 4^2 + 2^2 + 0 = 16 + 4 = 20
When you use zero the you increase the sum of the squares.
Then the three numbers that yields the minimum sum of the squares is 1, 2 and 3.
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